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Hint: it has to do with a 'recipe' that many math lessons follow. How does the calculator find values of sine or cosine or tangent? Here's a question I once received from a reader: Exactly what happens when I type the sine or cos or tan etc for that matter of an angle into my calculator? Then use the above formula to get the value of sin 0. It is an interesting field of mathematics, and one that has lots of applications.

The branch of mathematics called numerical methods studies and develops these algorithms. In fact, a calculator uses some kind of algorithm based on the basic operations not only to calculate trigonometric values, but also square roots, values of hyperbolic functions and others. The Cordic algorithm is based on thinking of the angle as the phase of a complex number in the complex plane, and then rotating the complex number by multiplying it by a succession of constant values. In fact, they look identical in the image, but we know they are not exactly the same, just very very close - even the above calculation shows that.

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See how closely the polynomial formed from the first four terms of the Taylor series approximates the sine curve near the origin. One way is to take a certain amount of terms the more terms you take, the more accurate the approximation from the Taylor series for sine. Is the calculator just reading off of a list created from people who used rulers to physically measure the distance on a graph or is there a mathematical function that defines it? A calculator or computer program is not reading off of a list, but is using an algorithm that gives an approximate value for the sine of a given angle. I type it in and it magically gives me an answer, a number that is essentially unrelated to the angle I inputed. Permanent Link.Exactly what happens when I type the sine or cos or tan etc for that matter of an angle into my calculator?

Practical applications of topological insulators Getting Started: Have something to contribute to this discussion? Please be thoughtful, detailed and courteous, and adhere to our posting rules.

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Please post the code that you tried and why it fails. I tried both solution but it does not work on my python v. It will however print messages as many times as you enter a speed less than 5 or greater than I would remove the if statement in that loop, otherwise you print information twice Edited 4 Years Ago by woooee. The first time the speed was 3, so it prints 'Clocked speed must be faster than 5mph', and asks again since the speed wasn't between It is the while loop that is doing this, not the if statements. One if the speed is less than 5 and another if it is greater than They are there so that nothing is printed for speeds between 5 and That's why I say it's redundant, and why the if: elif: pair should be taken out Clocked speed must be faster than 5mph and less than mph What was your clocked speed? This is indeed how it is supposed to work. If you have 2 while loops in a row, then you will have to enter the data twice, once for each loop.

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Is this right? I don't know how to make is so that once it asks for the limit again to set the parameters so it won't accept a number that is less than 10 or more than Note that if someone enters anything other than a number, the program will fail, but It doesn't say anything about testing the input so you are probably OK as is. But I'm trying to make it so that the limit can not be less than 10 or more than 90, and in the 2nd function it has to validate the clocked speed, it can not be less than 5 or more than I must loops to do the validation. I don't know why I keep getting an error in the last line. The first function should accept the speed limit, the 2nd function should accept the clocked speed, and the third function should determine and print the fine, if there is one, or print a message indicating that hte speed was legal. So my semester is almost over and I was dumb when I signed up for intro to programming distance learning, I thought I would understand it, but now I guess I know I can't.

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